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IB DP Physics Study Notes

9.1.2 Energy Conservation in SHM

Simple Harmonic Motion (SHM) is a captivating domain of physics due to its repetitive, predictable motion and the central role played by energy conservation. The rhythmic dance between potential and kinetic energy not only defines this type of motion but also ensures that the total energy in an undamped system remains constant.

Potential Energy in SHM

In SHM, potential energy comes to the forefront particularly when the object is maximally displaced from its equilibrium position. At this extremity of motion, all the energy of the system is potential.

Understanding the Spring-Mass System

Let's delve into a classic model in SHM: a mass attached to a spring. When you stretch or compress a spring and then let go, the mass starts to oscillate. The further you displace the mass from its equilibrium position, the larger the restoring force and the greater the potential energy stored in the system. Mathematically:

U = 0.5 * k * x2

Where:

  • U represents the potential energy.
  • k is the spring constant that dictates the stiffness of the spring.
  • x is the displacement from the equilibrium.

Gravity's Role in Pendulum Systems

In the case of pendulums, gravitational potential energy comes into play. As the pendulum reaches its maximum height during the swing, its potential energy is maximal due to gravity. The formula in this context is:

U = m * g * h

Where:

  • m is the mass of the pendulum bob.
  • g is the acceleration due to gravity.
  • h is the vertical height the bob is displaced from its lowest point.

Kinetic Energy in SHM

The kinetic energy in an SHM system is highest when the oscillating object passes through the equilibrium position. This is because its velocity is maximal here.

K = 0.5 * m * v2

Where:

  • K denotes kinetic energy.
  • m represents the mass of the object.
  • v is its velocity.

This kinetic energy diminishes as the object approaches the extremities of its motion, eventually becoming zero when the object momentarily stops before changing direction.

Deducing Velocity in SHM

By leveraging the laws of energy conservation, one can deduce the velocity at any point in the motion. Using the spring-mass system as an example:

Total energy = U + K From which: v = sqrt( (k/m) * (A2 - x2) )

Where A represents the amplitude of motion. This relationship showcases the direct connection between energy and the object's position in its oscillatory path.

Transition between Potential and Kinetic Energy

The beauty of SHM is in the flawless transition between its potential and kinetic energy:

  1. Amplitude Points: Here, potential energy is at its zenith. The system's entire energy is stored as potential energy due to the displacement of the object. Kinetic energy is null because the object is momentarily stationary.
  2. Equilibrium Point: As the object glides through its midpoint or equilibrium, kinetic energy surges, capturing all the system's energy. Potential energy is nil since there's no displacement from the equilibrium.
  3. In-between: Between these two extremes, both forms of energy coexist, but their sum remains constant, embodying the essence of energy conservation in SHM.

Implications of Energy Conservation

Predicting Future States

Given an SHM system's current energy distribution, one can forecast its next state. For instance, if a pendulum possesses significant potential energy and negligible kinetic energy, we can predict that it's near its turning point and about to swing back.

SHM in the Real World

From quartz watches to musical instruments, the principles of SHM are prevalent in our daily lives. Recognising the shifts between potential and kinetic energy aids in comprehending and designing such devices and systems.

Safety and Engineering

In sectors like civil engineering, understanding SHM's energy transitions is crucial. For instance, buildings in earthquake-prone areas are designed to absorb and dissipate energy, emulating damped harmonic motion. This knowledge helps in safeguarding structures and lives.

FAQ

In an ideal scenario, the total energy in an SHM system remains constant. However, in real-world scenarios, there are energy losses primarily due to resistive forces like friction or air resistance. When an object moves through air, for instance, it has to push air molecules out of the way, leading to energy dissipation. Similarly, in a spring-block system on a surface, friction between the block and the surface can sap energy from the system. This is why real-world SHM systems eventually come to a stop unless there's an external force or energy input.

It's essential to understand that while the kinetic energy is zero at maximum displacement, the potential energy is at its peak. This potential energy acts as a 'stored' energy that propels the object back into motion. The object possesses restoring forces (like spring force in a mass-spring system or gravitational force in a pendulum) that push or pull it back towards its equilibrium position. As it moves, the potential energy gets converted back into kinetic energy. Thus, even though kinetic energy momentarily becomes zero, the motion doesn't stop due to the continuous energy transitions.

The frequency of oscillation doesn't directly affect the total energy in an SHM system, but it determines the rate at which energy transitions between kinetic and potential forms. A higher frequency means the object oscillates back and forth more times per second, leading to quicker energy transitions. For a given amplitude, an increase in frequency doesn't increase the total energy but makes the oscillating object reach its maximum and minimum energy values more frequently within a set period.

Energy conservation is pivotal in SHM. As the object moves from its equilibrium position towards maximum displacement, its kinetic energy (energy due to motion) decreases while its potential energy (energy due to position) increases. Conversely, as it moves back towards the equilibrium position, the potential energy decreases and the kinetic energy increases. This interplay ensures that the total energy remains constant throughout the motion. Even though energy is continuously transferred between kinetic and potential forms, no energy is lost from the system, allowing the object to oscillate indefinitely in an ideal frictionless environment.

In Simple Harmonic Motion (SHM), maximum displacement is referred to as the amplitude of the oscillation. At this point, the object has been moved to the farthest point from its equilibrium position, and thus it momentarily comes to rest before moving back. As a result, its velocity is zero, and consequently, its kinetic energy (which is dependent on velocity) is also zero. On the other hand, the potential energy is maximum at this point because the object is at its maximum distance from the equilibrium position, and it has maximum potential to move or to do work.

Practice Questions

A 0.5 kg mass attached to a spring oscillates with an amplitude of 0.1 m. When the spring is compressed by 0.05 m, the kinetic energy of the mass is 1.25 J. Calculate the spring constant, k.

In this scenario, we're given: Mass, m = 0.5 kg Amplitude, A = 0.1 m Displacement, x = 0.05 m Kinetic energy at x, K = 1.25 J

Using the conservation of energy principle, at displacement x, the sum of potential and kinetic energy is equal to the potential energy at amplitude: 0.5 * k * A2 = 0.5 * k * x2 + K Substituting in the given values and rearranging, we obtain: k = 2(K + 0.5 * k * x2) / A2 Upon solving, the value of k is found to be 500 N/m.


A pendulum is displaced such that its bob is raised by 0.2 m. If the mass of the bob is 0.75 kg, determine its kinetic energy when it passes through its lowest point.

Given: Height, h = 0.2 m Mass, m = 0.75 kg g (acceleration due to gravity) = 9.81 m/s2

At the highest point, the potential energy, U = m * g * h. When the pendulum bob passes through its lowest point, all this potential energy will have been converted into kinetic energy. Therefore, K = m * g * h. Using the values provided: K = 0.75 kg * 9.81 m/s2 * 0.2 m = 1.4775 J.

Thus, the kinetic energy of the bob as it passes through its lowest point is 1.4775 J.

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