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CIE A-Level Maths Study Notes

2.8.2 Solving Separable Differential Equations

In this comprehensive exploration, we focus on separable differential equations. These equations, pivotal in modelling various real-world phenomena, require adept use of integration techniques for their solutions.

Understanding Separable Differential Equations

Separable differential equations can be written as dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y), where g(x)g(x) and h(y)h(y) are functions solely of xx and yy respectively. The solution process involves separating the variables xx and yy, and then integrating both sides of the equation.

Key Integration Techniques

To solve these equations, students must be familiar with three key integration techniques: integration by substitution, integration by parts, and the method of partial fractions. Each technique is suited to different types of differential equations and is crucial for finding the general solution.

Examples Illustrating These Methods

Example 1: Basic Separation of Variables

Problem: Solve dydx=x2y\frac{dy}{dx} = x^2y.

Solution:

1. Separate Variables: Rearrange to 1ydy=x2dx\frac{1}{y}dy = x^2dx.

2. Integrate Both Sides:

  • Integrate x2x^2 with respect to xx, giving x33\frac{x^3}{3}.
  • Integrate 1y\frac{1}{y} with respect to yy, giving lny\ln|y|.

3. Combine Results: The solution is lny=x33+C\ln|y| = \frac{x^3}{3} + C, where CC is the constant of integration.

Example 2: Integration by Parts

Problem: Solve dydx=exy\frac{dy}{dx} = \frac{e^x}{y}.

Solution:

1. Rearrange Equation: Convert to ydy=exdxydy = e^xdx.

2. Integrate Both Sides:

  • Integrate exe^x with respect to xx, yielding exe^x.
  • Integrate ydyydy, resulting in y22\frac{y^2}{2}.

3. Combine Results: The general solution is y22=ex+C\frac{y^2}{2} = e^x + C.

Example 3: Using Partial Fractions

Problem: Solve dydx=4x(x2+1)y\frac{dy}{dx} = \frac{4x}{(x^2+1)y}.

Solution:

1. Rearrange Equation: Modify to ydy=4xx2+1dxydy = \frac{4x}{x^2+1}dx.

2. Integrate Using Partial Fractions:

  • Integrate 4xx2+1\frac{4x}{x^2+1} with respect to xx, which results in 2lnx2+12\ln|x^2+1|.
  • Integrate ydyydy, yielding y22\frac{y^2}{2}.

3. Combine Results: The solution is y22=2lnx2+1+C\frac{y^2}{2} = 2\ln|x^2+1| + C.

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