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AQA GCSE Chemistry Notes

3.3.8 Yield and Purity Calculations

Percentage Yield

Understanding Percentage Yield

Percentage yield is a key indicator of the efficiency of a chemical reaction. It compares the amount of product actually obtained to the theoretical maximum amount that could be produced based on stoichiometry.

Calculation of Percentage Yield

  1. Determining Theoretical Yield: Begin by calculating the theoretical yield. This requires a thorough understanding of the balanced chemical equation and the concept of molar ratios. The theoretical yield is the maximum possible amount of product expected, as predicted by stoichiometric calculations.
  2. Measuring Actual Yield: The actual yield is the amount of product actually produced and measured in a laboratory setting. This value is often less than the theoretical yield due to various practical limitations.
  3. Formula for Percentage Yield: ( \text{Percentage Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\% )

Example

Consider the reaction between hydrogen and oxygen to form water. If the balanced equation predicts a theoretical yield of 12 grams of water, but the experiment only produces 10 grams, the percentage yield is calculated as: ( \left( \frac{10 \text{ g}}{12 \text{ g}} \right) \times 100\% = 83.33\% )

Diagrammatic presentation of Actual yield vs theoretical yield concept

Image courtesy of Expii

Composition by Mass

Fundamentals of Composition

Composition by mass gives an insight into the proportion of each element within a compound. This concept is crucial for understanding the makeup of chemical substances.

Methods to Calculate Composition

  1. Utilising Relative Atomic Masses: The calculation involves using the relative atomic masses of the elements present in the compound.
  2. Mass Percentage Formula: ( \text{Mass Percentage} = \left( \frac{\text{Mass of element in compound}}{\text{Total mass of compound}} \right) \times 100\% )

Example

In a water molecule (H₂O), the molar mass is 18 g/mol. The contribution of hydrogen is 2 g/mol and oxygen is 16 g/mol. Therefore, the mass percentages are:

  • Hydrogen: ( \left( \frac{2 \text{ g/mol}}{18 \text{ g/mol}} \right) \times 100\% = 11.11\% )
  • Oxygen: ( \left( \frac{16 \text{ g/mol}}{18 \text{ g/mol}} \right) \times 100\% = 88.89\% )

Purity Calculations

Defining Purity in Chemistry

Purity is a measure of the amount of a desired substance within a mixture. It is particularly significant in the synthesis and analysis of chemical compounds.

Steps to Calculate Purity

  1. Determine the Mass of the Pure Substance: This involves isolating and measuring the component of interest within the sample.
  2. Ascertain the Total Mass of the Sample: The total sample mass includes both the desired substance and any impurities.
  3. Purity Calculation Formula: ( \text{Purity} = \left( \frac{\text{Pure Substance Mass}}{\text{Total Sample Mass}} \right) \times 100\% )

Example

Consider a sample of calcium carbonate where 95g is pure CaCO₃ and the total sample mass is 100g. The purity is calculated as: ( \left( \frac{95 \text{ g}}{100 \text{ g}} \right) \times 100\% = 95\% )

Practical Applications and Importance

Laboratory Applications

  • Optimising Reaction Conditions: Understanding and calculating yield and purity helps in fine-tuning reaction conditions to achieve maximum efficiency.
  • Quality Assurance: These concepts are critical in quality control processes, especially in the pharmaceutical and food industries, to ensure the safety and consistency of products.
Chemistry laboratory experimental setup

Image courtesy of ITM Vocational University

Industrial Relevance

  • Cost-Efficiency: In industrial chemistry, achieving high yields and purities is essential for the economic viability of processes.
  • Environmental Considerations: Efficient chemical processes with higher yields reduce waste production, thereby mitigating environmental impact.

Challenges in Achieving High Yield and Purity

  • Practical Limitations: Factors such as incomplete reactions, side reactions, and loss of product during processing often lead to lower yields.
  • Purity Concerns: Contamination, side products, and incomplete separation methods can affect the purity of the final product.

Strategies for Improvement

  • Optimising Reaction Conditions:Adjusting factors like temperature, pressure, and reactant concentrations can improve yields.
  • Advanced Purification Techniques: Employing sophisticated methods like chromatography and recrystallisation can enhance purity.

In conclusion, the concepts of yield and purity are not only central to theoretical chemistry but also have profound practical implications. Their accurate calculation is a skill that IGCSE Chemistry students must master, serving as a foundation for their future explorations in the field of chemistry. Understanding these concepts enriches students' theoretical knowledge and enhances their practical skills, which are indispensable in real-world applications.

FAQ

Understanding and calculating the composition by mass in a compound is essential for several reasons. Firstly, it helps in determining the formula of the compound, which is fundamental in understanding its chemical properties and behavior. Knowing the composition by mass is crucial for predicting how compounds will react with each other. This is particularly important in fields like pharmaceuticals, where precise composition determines the effectiveness and safety of drugs. Additionally, it aids in the identification and characterization of unknown substances in chemical analysis. In industrial chemistry, accurate knowledge of composition is vital for quality control and ensuring that products meet specified standards. For students, mastering this concept builds a strong foundation in chemical stoichiometry and analytical chemistry, skills that are valuable in advanced studies and practical applications.

Common mistakes made by students when calculating percentage yield include errors in stoichiometric calculations, inaccurate measurements of reactants and products, and misunderstanding the concept of limiting reactants. To avoid these errors, students should ensure they fully understand the stoichiometry of the reaction, including the molar ratios of reactants and products. Accurate measurements are crucial; hence, using precise measuring equipment and techniques is important. Students should also be aware of the concept of limiting reactants, as this determines the theoretical yield of the reaction. Additionally, paying attention to unit conversions and ensuring consistency in units throughout the calculation can prevent errors. Regular practice with a variety of problems and seeking clarification on any misunderstood concepts are effective ways to improve accuracy in calculating percentage yield.

In pharmaceutical industries, the concept of purity is of utmost importance as it directly affects the safety and efficacy of medications. Purity in this context refers to the absence of unwanted chemicals, which could be unreacted starting materials, byproducts, or contaminants. Ensuring high purity levels is crucial because even small amounts of impurities can significantly impact the therapeutic effect of a drug and may pose health risks. To maintain high standards of purity, rigorous analytical methods like high-performance liquid chromatography (HPLC), gas chromatography, and mass spectrometry are employed. These techniques allow for the precise determination of the purity of the active pharmaceutical ingredients (APIs) and the final product. Furthermore, stringent regulatory standards and quality control protocols are in place to ensure that all pharmaceutical products meet the required purity specifications before they reach consumers.

The actual yield in chemical reactions is frequently less than the theoretical yield due to a variety of practical factors. Firstly, not all reactants in a reaction may convert to products. This incomplete reaction is often due to the reaction reaching equilibrium, where reactants and products exist in a balanced state, or due to the reaction's kinetics which might be slow. Secondly, side reactions can occur, producing other products and thus reducing the yield of the desired product. Additionally, there can be losses of product during the practical stages of the experiment, such as during filtration, transfer, or evaporation processes. In real-world settings, impurities in reactants and variations in experimental conditions like temperature and pressure also contribute to the reduced actual yield. These factors combined mean that the actual yield is usually lower than the theoretically calculated maximum yield.

In environmental chemistry, purity calculation plays a significant role in assessing and controlling pollution. Determining the purity of environmental samples, such as water, air, or soil, is crucial in identifying the presence and concentration of pollutants. By calculating the purity of these samples, scientists can assess the level of contamination and identify specific pollutants, which is essential for environmental monitoring and remediation efforts. High-precision analytical techniques are used to detect and quantify trace levels of contaminants, allowing for the evaluation of their impact on ecosystems and human health. Furthermore, understanding the purity of chemicals used in industrial processes helps in minimizing the release of harmful substances into the environment. Effective purity analysis is key in developing strategies for pollution control, ensuring compliance with environmental regulations, and promoting sustainable practices that protect the environment.

Practice Questions

In an experiment to produce salt from a reaction, the theoretical yield of the salt is calculated to be 25 grams. However, only 18 grams of salt were actually produced. Calculate the percentage yield of the salt. Show your working.

To calculate the percentage yield, the formula (\text{Percentage Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\% ) is used. The actual yield obtained from the experiment is 18 grams, and the theoretical yield is 25 grams. Substituting these values into the formula gives: (\text{Percentage Yield} = \left( \frac{18 \text{ g}}{25 \text{ g}} \right) \times 100\% = 72\%). Therefore, the percentage yield of the salt in this experiment is 72%, which indicates the efficiency of the reaction in producing the expected product.

A sample of a compound was found to contain 15 grams of nitrogen and 35 grams of oxygen. Calculate the percentage composition by mass of nitrogen and oxygen in the compound.

The percentage composition by mass is calculated using the formula (\text{Mass Percentage} = \left( \frac{\text{Mass of element in compound}}{\text{Total mass of compound}} \right) \times 100\%). The total mass of the compound is the sum of the masses of nitrogen and oxygen, which is (15 \text{ g} + 35 \text{ g} = 50 \text{ g}). The mass percentage of nitrogen is (\left( \frac{15 \text{ g}}{50 \text{ g}} \right) \times 100\% = 30\%), and for oxygen, it is (\left( \frac{35 \text{ g}}{50 \text{ g}} \right) \times 100\% = 70\%). Therefore, the compound consists of 30% nitrogen and 70% oxygen by mass.

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