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IB DP Maths AI SL Study Notes

5.1.2 Differentiation Rules

Power Rule

The power rule is one of the most fundamental rules in differentiation and is usually one of the first rules taught in calculus. Understanding the basics of differentiation is essential, as detailed in our introduction to derivatives.

Definition

If f(x) = xn, where n is a real number, then the derivative is given by: f'(x) = nx(n-1)

Example Question 1

Find the derivative of f(x) = x5.

Solution:

Using the power rule, we get: f'(x) = 5x(5-1) = 5x4

Product Rule

The product rule is used when differentiating the product of two functions. This rule is a stepping stone to more complex applications, such as curve sketching, which relies on understanding the behaviour of derivatives.

Definition

If f(x) = g(x) * h(x), then the derivative is given by: f'(x) = g'(x)h(x) + g(x)h'(x)

Example Question 2

Find the derivative of f(x) = (2x + 3)(x2 - 1).

Solution:

Let g(x) = 2x + 3 and h(x) = x2 - 1. g'(x) = 2 and h'(x) = 2x Using the product rule: f'(x) = g'(x)h(x) + g(x)h'(x) f'(x) = 2(x^2 - 1) + (2x + 3)(2x) f'(x) = 2x2 - 2 + 4x2 + 6x f'(x) = 6x2 + 6x - 2

Quotient Rule

The quotient rule is used to find the derivative of the quotient of two functions. A deeper dive into applications of differentiation can further illustrate how this rule is applied in various mathematical scenarios.

Definition

If f(x) = g(x) / h(x), then the derivative is given by: f'(x) = (g'(x)h(x) - g(x)h'(x)) / [h(x)]2

Example Question 3

Find the derivative of f(x) = (x2 + 1) / (x - 2).

Solution:

Let g(x) = x2 + 1 and h(x) = x - 2. g'(x) = 2x and h'(x) = 1 Using the quotient rule: f'(x) = (g'(x)h(x) - g(x)h'(x)) / [h(x)]2 f'(x) = (2x(x - 2) - (x2 + 1)(1)) / (x - 2)2 f'(x) = (2x2 - 4x - x2 - 1) / (x - 2)2 f'(x) = (x2 - 4x - 1) / (x - 2)2

Application in Curve Analysis

Understanding and applying these differentiation rules is crucial in analysing and understanding the behaviour of functions, especially in determining the slope of a tangent line at a particular point, finding local maxima and minima, and understanding the concavity of functions. These applications are not only pivotal in pure mathematics but also play a significant role in various fields such as physics, economics, and engineering, where understanding the rate of change is crucial. For more comprehensive applications, consider exploring the areas between curves and how differentiation rules apply.

Moreover, understanding how rates change in relation to each other is explored through related rates, a fascinating application of differentiation that deals with the rate at which one quantity changes in relation to another.

FAQ

A common mistake is neglecting to apply the chain rule when it's required, especially when dealing with composite functions or functions within functions. For instance, when differentiating a function like f(x) = (2x + 3)2, students might incorrectly apply the power rule directly without considering the inner function 2x + 3. The correct approach would involve applying the chain rule: f'(x) = 2(2x + 3)(2), derived by differentiating the outer function and multiplying it by the derivative of the inner function. Another common error is misapplying the product and quotient rules, such as forgetting to square the denominator in the quotient rule or neglecting to include all terms in the product rule.

The product rule can be extended to the product of more than two functions by applying it sequentially. Suppose you have three functions being multiplied together: f(x) = g(x)h(x)i(x). To find the derivative, you would differentiate one function at a time while keeping the others constant, and then add those derivatives together. Mathematically, f'(x) = g'(x)h(x)i(x) + g(x)h'(x)i(x) + g(x)h(x)i'(x). This method can be extended to any number of functions being multiplied together by differentiating each function in turn, multiplying by the remaining undifferentiated functions, and summing all the results.

Choosing the appropriate rule for differentiation typically depends on the form of the function you're dealing with. If you have a power of x, the power rule is most direct. For a product of two functions, the product rule is apt, and for a quotient of two functions, the quotient rule is suitable. In cases where you have a composite function (a function within a function), the chain rule is necessary. Often, real-world problems involve combinations of these rules. Identifying the overarching structure of the function and breaking it down into manageable parts will guide the choice of which rule(s) to apply and in what order to ensure accurate differentiation.

The quotient rule is specifically designed to efficiently find the derivative of a quotient of two functions. While it might seem possible to rewrite a quotient as a product, for example, f(x) = g(x)h(x)(-1), and then use the product rule, this method actually becomes cumbersome and less straightforward. Using the product rule in this way would still require you to find the derivative of h(x)(-1), which is a quotient! Thus, the quotient rule, f'(x) = (g'(x)h(x) - g(x)h'(x)) / [h(x)]2, provides a direct and simplified method for finding the derivative of a quotient of two functions, ensuring accuracy and efficiency in calculations.

Yes, the power rule for differentiation can be applied to any real number power of x, including negative and fractional exponents. The general form of the power rule, d/dx[xn] = nx(n-1), is applicable in these cases. For instance, if you have a function f(x) = x(-3), using the power rule, its derivative would be f'(x) = -3x(-4). Similarly, for fractional powers like f(x) = x(1/2) (which is the square root of x), the derivative using the power rule would be f'(x) = (1/2)x(-1/2). The power rule is incredibly versatile and can be applied in a wide range of contexts, making it a fundamental tool in calculus.

Practice Questions

Differentiate the following function using the product rule: f(x) = (3x^2 + 2)(x^3 - 4x).

The product rule of differentiation states that if we have a function f(x) = g(x)h(x), then its derivative, f'(x), is given by: f'(x) = g'(x)h(x) + g(x)h'(x) Let's identify our functions here: g(x) = 3x2 + 2 h(x) = x3 - 4x Now, we find the derivatives of g(x) and h(x): g'(x) = 6x h'(x) = 3x^2 - 4 Applying the product rule: f'(x) = (6x)(x3 - 4x) + (3x2 + 2)(3x2 - 4) f'(x) = 6x4 - 24x2 + 9x4 - 12x2 + 6x2 - 8 f'(x) = 15x4 - 30x2 - 8

Differentiate the following function using the quotient rule: f(x) = (4x^3 + 2x^2 - x + 1) / (x^2 + 1).

The quotient rule of differentiation states that if we have a function f(x) = g(x) / h(x), then its derivative, f'(x), is given by: f'(x) = (g'(x)h(x) - g(x)h'(x)) / [h(x)]2 Let's identify our functions here: g(x) = 4x3 + 2x2 - x + 1 h(x) = x2 + 1 Now, we find the derivatives of g(x) and h(x): g'(x) = 12x2 + 4x - 1 h'(x) = 2x Applying the quotient rule: f'(x) = (12x2 + 4x - 1)(x2 + 1) - (4x3 + 2x2 - x + 1)(2x) / (x2 + 1)2 f'(x) = (12x4 + 4x3 - x2 + 12x2 + 4x - 1 - (8x4 + 4x3 - 2x2 + 2x)) / (x2 + 1)2 f'(x) = (4x4 + 13x2 + 2x - 1) / (x2 + 1)2

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