TutorChase logo
IB DP Maths AI SL Study Notes

5.1.1 Introduction to Derivatives

Tangent Lines

A tangent line to a curve at a particular point is the straight line that just "touches" the curve at that point. This implies that near this point, the curve and the line have approximately the same slope. Let’s delve deeper into understanding this concept. For a foundational understanding, refer to the introduction to derivatives.

Definition

The tangent line to the curve y = f(x) at the point P(a, f(a)) is the line that passes through P and has slope equal to the limit:

mT = lim(h -> 0) (f(a + h) - f(a)) / h

where mT is the slope of the tangent line. Familiarise yourself with the differentiation rules to understand how derivatives are calculated, which is essential for finding the slope of tangent lines.

Significance

  • Local Linearity: At a small scale, the curve appears almost linear, and the tangent line represents this local linearity.
  • Instantaneous Rate of Change: The slope of the tangent line represents the instantaneous rate of change of the function at point P. This is a critical concept in applications of differentiation, where derivatives help solve real-world problems.

Example Question 1

Find the equation of the tangent line to the curve y = x2 at the point P(2, 4).

Solution:

1. Find the Derivative: The derivative of y = x2 is y' = 2x.

2. Evaluate the Derivative at P: y'(2) = 2 * 2 = 4.

3. Use Point-Slope Form: The equation of the tangent line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point of tangency. Substituting in our values: y - 4 = 4(x - 2). Simplifying the equation: y = 4x - 8 + 4 y = 4x - 4

Visual Representation

The graphical representation of the derivative of x^2 is a straight line, which is evident from the plot below.

null

This plot illustrates the derivative 2x across a range of x values. The linearity of the graph signifies the constant rate of change, which is a characteristic of power functions with an exponent of 2.

Rates of Change

The derivative also provides us with a powerful tool to analyse rates of change in various contexts, such as physics, economics, and biology. The derivative f'(x) gives the rate of change of f with respect to x. Understanding the related rates can further enhance your grasp on how changes in one quantity can affect another.

Average Rate of Change

The average rate of change of f from x1 to x2 is given by:

(Delta f) / (Delta x) = (f(x2) - f(x1)) / (x2 - x1)

Instantaneous Rate of Change

The instantaneous rate of change of f at x is given by:

f'(x) = lim(h -> 0) (f(x + h) - f(x)) / h

Example Question 2

Given f(x) = 3x3 - 5x, find the instantaneous rate of change at x = 2.

Solution:

1. Find the Derivative: f'(x) = 9x2 - 5.

2. Evaluate at the Point: f'(2) = 9 * 22 - 5 = 31.

Thus, the instantaneous rate of change of f at x = 2 is 31.

Applications in Real-World Contexts

Physics: Velocity and Acceleration

  • Velocity is the rate of change of displacement with respect to time and is given by the first derivative of the displacement function.
  • Acceleration is the rate of change of velocity with respect to time and is given by the second derivative of the displacement function.

Economics: Marginal Cost and Revenue

  • Marginal Cost is the rate of change of total cost with respect to the number of units produced and is found using the first derivative of the cost function.
  • Marginal Revenue is the rate of change of total revenue with respect to the number of units sold and is found using the first derivative of the revenue function.

Biology: Population Growth Rate

  • The rate of change of population with respect to time, often referred to as the population growth rate, can be modelled using derivatives.

Example Question 3

A particle moves along a line so that its position at any time t is given by s(t) = t2 - 3t + 2. Find the velocity at t = 4 seconds.

Solution:

1. Find the Derivative: v(t) = s'(t) = 2t - 3.

2, Evaluate at the Point: v(4) = 2 * 4 - 3 = 5.

Thus, the velocity of the particle at t = 4 seconds is 5 m/s. For further exploration of motion analysis, see curve sketching, which provides insights into how derivatives influence the shape of a graph.

FAQ

The points where the derivative of a function is zero or undefined are critical in understanding the function’s behaviour and are aptly termed critical points. When the derivative is zero, it implies that the tangent line to the curve at that point is horizontal, which might indicate a local maximum, local minimum, or a saddle point. When the derivative is undefined, it might suggest a cusp or a vertical tangent line. Analyzing critical points is fundamental in various calculus applications, such as determining the relative extrema of a function, sketching the graph of a function, and solving optimisation problems, thereby providing a comprehensive view of the function's behaviour.

Yes, the second derivative, which is essentially the derivative of the first derivative, plays a crucial role in determining the concavity of a function. If the second derivative of a function is positive at a particular point, the function is concave up (shaped like a U) at that point. Conversely, if the second derivative is negative, the function is concave down (shaped like an inverted U) at that point. The concavity provides insights into the behaviour of the function, such as identifying intervals where the function is increasing or decreasing at an increasing rate, which is vital in various applications like optimisation problems.

In biology, particularly in population dynamics, derivatives are used to describe the rate of change of population size with respect to time. The derivative, termed as the population growth rate, can be modelled using various equations, such as the exponential growth model or the logistic growth model, depending on the ecological assumptions and constraints. For instance, in the logistic growth model, the rate of change of population (dP/dt) is proportional to both the current population size (P) and the amount of available resources (K - P), where K is the carrying capacity. Thus, derivatives in biology help in understanding and predicting population sizes, which is crucial for conservation biology, resource management, and understanding ecological dynamics.

Tangent lines are pivotal in calculus as they provide a linear approximation to a function at a particular point. In the realm of derivatives, the slope of the tangent line at a given point on the curve represents the instantaneous rate of change of the function at that point. This concept is crucial in understanding and interpreting the behaviour of functions, especially in the vicinity of the point of tangency. Furthermore, tangent lines are instrumental in various applications of calculus, such as predicting future values of a function, analysing cost and revenue in economics, and understanding motion in physics, thereby making them an indispensable concept in calculus.

Derivatives in calculus are fundamentally linked to the concept of rate of change, which is ubiquitously applicable in various real-world scenarios. In physics, for instance, the derivative of a position function with respect to time gives the velocity, representing the rate of change of position. Similarly, in economics, the derivative of a cost function with respect to the quantity of items produced gives the marginal cost, indicating how much additional cost will be incurred by producing one more item. Thus, derivatives provide a mathematical framework to model, analyse, and predict changes in one variable relative to changes in another, which is pivotal in diverse fields for decision-making and problem-solving.

Practice Questions

Find the equation of the tangent line to the curve y = x^3 - 2x^2 + x at the point where x = 3.

To find the equation of the tangent line, we first need to find the derivative of the given function, which will give us the slope of the tangent line at any point x. The derivative of y = x3 - 2x2 + x is y' = 3x2 - 4x + 1. Now, substituting x = 3 into the derivative, we get the slope of the tangent line at x = 3, which is y'(3) = 3 * 32 - 4 * 3 + 1 = 16. The y-coordinate of the point of tangency can be found by substituting x = 3 into the original function: y(3) = 33 - 2 * 32 + 3 = 12. Therefore, the point of tangency is P(3, 12). Using the point-slope form of a line, y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point of tangency, we get the equation of the tangent line: y - 12 = 16(x - 3). Simplifying the equation: y = 16x - 48 + 12 y = 16x - 36.

A particle moves along a straight line such that its position at any time t (in seconds) is given by s(t) = t^2 - 4t + 3. Find the velocity of the particle at t = 2 seconds.

To find the velocity of the particle at a particular time, we need to find the derivative of the position function with respect to time, which gives us the velocity function. The derivative of s(t) = t2 - 4t + 3 is s'(t) = 2t - 4. Now, substituting t = 2 into the derivative, we get the velocity of the particle at t = 2 seconds, which is s'(2) = 2 * 2 - 4 = 0. Therefore, the velocity of the particle at t = 2 seconds is 0 m/s, meaning the particle is momentarily at rest at this time instant.

Hire a tutor

Please fill out the form and we'll find a tutor for you.

1/2
About yourself
Alternatively contact us via
WhatsApp, Phone Call, or Email