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IB DP Maths AI HL Study Notes

1.2.2 Logarithmic Functions

Understanding Logarithms

Logarithms, often abbreviated as "logs", serve as a mechanism to solve for exponents in exponential equations and determine the rate of exponential growth or decay. The logarithm, written as logb(a), poses the question: to what power must the base (b) be raised to obtain a? For a deeper understanding of how logarithms relate to exponential functions, see our notes on exponential functions.

Basic Properties of Logarithms

  • Product Rule: logb(mn) = logb(m) + logb(n)
  • Quotient Rule: logb(m/n) = logb(m) - logb(n)
  • Power Rule: logb(mn) = n * logb(m)
  • Change of Base Rule: logb(a) = logc(a) / logc(b), where c is any positive number different from 1. This principle is especially useful when the base of the logarithm we're working with is not immediately available on a standard calculator, as further explained in our notes on inverse functions.

Example Question 1

Solve for x in the equation 3(2x) = 81.

Solution: Using logarithms, we can rewrite the equation as 2x = log3(81). Since 81 is 34, we can simplify further to 2x = 4, resulting in x = 2.

Change of Base Formula

The change of base formula allows us to compute the logarithm of a number in one base using logarithms in another base. This is particularly useful when dealing with logarithms in bases other than 10 or e, which are typically available on calculators. For applications of this formula in calculus, refer to our section on differentiation of exponential and logarithmic functions.

Application of Change of Base

  • Calculations: Simplifying logarithmic expressions or calculations when the base is not readily available on standard calculators.
  • Solving Equations: Facilitating the solution of logarithmic and exponential equations by converting them to a familiar or more straightforward base.

Example Question 2

Evaluate log5(25) using the change of base formula with base 10.

Solution: Using the change of base formula, log5(25) = log10(25) / log10(5). Calculating the values, we get log5(25) = 1.4 / 0.7 = 2, since 25 is 52.

Properties of Logarithms

The properties of logarithms are essential tools that allow us to simplify and solve logarithmic and exponential expressions and equations. These properties are derived from the corresponding properties of exponents and provide a pathway to manipulate logarithmic expressions into more workable forms. To see these properties applied in more complex scenarios, visit our detailed notes on logarithmic functions.

Utilising Properties in Simplification

  • Combining Logarithms: Using the product and quotient rules to combine logarithmic expressions into a single logarithm.
  • Expanding Logarithms: Employing the product, quotient, and power rules to expand a logarithm into a sum or difference of logarithms.

Example Question 3

Simplify log2(32) - log2(4) using logarithm properties.

Solution: Using the quotient rule, log2(32) - log2(4) = log2(32/4) = log2(8). Since 8 is 23, the expression simplifies to log2(23) = 3, using the power rule.

Applications in Various Domains

Logarithmic functions permeate through various fields, including biology, finance, and physics, providing a robust mathematical framework to describe and predict phenomena, such as pH levels, sound intensity, and earthquake magnitudes, respectively.

pH Levels in Chemistry

In chemistry, the pH scale, which measures the acidity or basicity of a solution, is logarithmic. The pH is defined as pH = -log10([H+]), where [H+] is the concentration of hydrogen ions in the solution.

Richter Scale in Seismology

In seismology, the Richter scale, which quantifies the magnitude of earthquakes, employs logarithms. An increase of 1 unit on the Richter scale corresponds to a tenfold increase in the amplitude of the seismic waves.

Decibels in Acoustics

In acoustics, sound intensity levels are measured in decibels, which utilise logarithms to quantify the relative loudness of sounds. The decibel scale is defined as L = 10 * log10(I/I0), where I is the intensity of the sound and I0 is the reference intensity level.

Deep Dive into Logarithmic Properties

Understanding the properties of logarithms is crucial for simplifying expressions and solving equations. Let's delve deeper into each property and explore their applications. For those interested in how these properties integrate with calculus, our guide on integration of exponential and logarithmic functions offers a comprehensive look.

Product Rule in Detail

The product rule states that the logarithm of a product is the sum of the logarithms of the factors. Mathematically, logb(mn) = logb(m) + logb(n). This property is particularly useful when simplifying expressions involving multiplication inside a logarithm.

Example Question 4

Simplify log3(9 * 27).

Solution: Using the product rule, log3(9 * 27) = log3(9) + log3(27) = 2 + 3 = 5, since 9 is 32 and 27 is 33.

Quotient Rule in Detail

The quotient rule states that the logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator: logb(m/n) = logb(m) - logb(n). This property is useful for simplifying expressions involving division inside a logarithm.

Example Question 5

Simplify log7(49/7).

Solution: Using the quotient rule, log7(49/7) = log7(49) - log7(7) = 2 - 1 = 1, since 49 is 72.

Power Rule in Detail

The power rule states that the logarithm of a number raised to an exponent is equal to the exponent times the logarithm of the number: logb(mn) = n * log_b(m). This property is useful for simplifying expressions involving exponents inside a logarithm.

Example Question 6

Simplify log5(1253).

Solution: Using the power rule, log5(1253) = 3 * log5(125) = 3 * 3 = 9, since 125 is 53.

Change of Base Rule in Detail

The change of base rule allows us to calculate logarithms with any base using logarithms of a different base. It is expressed as logb(a) = logc(a) / logc(b), where c is any positive number different from 1. This property is especially useful when working with bases that are not readily available on standard calculators. For an in-depth exploration of this rule, check out our dedicated section on logarithmic functions.

Example Question 7

Evaluate log4(64) using the change of base formula with base 2.

Solution: Using the change of base formula, log4(64) = log2(64) / log2(4) = 6 / 2 = 3, since 64 is 26 and 4 is 22.

FAQ

The Richter scale employs logarithms to quantify the magnitude of earthquakes. The scale is logarithmic, meaning that each whole number increase on the scale represents a tenfold increase in measured amplitude and roughly 31.6 times more energy release. Specifically, the magnitude (M) is defined as M = log10(A) + 3log10(8T) - 2.92, where A is the maximum excursion of the Wood-Anderson seismometer, and T is the period of the seismic waves. The logarithmic scale allows for managing the wide-ranging amplitudes of seismic waves in a concise manner, providing clear and comprehensible data to scientists and the public.

Logarithms play a pivotal role in financial mathematics, particularly in calculating compound interest, which is crucial for evaluating investments, loans, and savings. The formula for compound interest, A = P(1 + r/n)(nt), where A is the amount, P is the principal, r is the rate, n is the number of times interest is compounded per unit t, and t is the time the money is invested or borrowed for, involves an exponent, which can be solved using logarithms when finding the time (t) or rate (r) in investment problems. Logarithms help to solve exponential equations in financial contexts, enabling analysts to make informed decisions regarding investments and loans.

Logarithms are used to measure sound intensity levels in decibels to accommodate the vast range of human hearing and describe sound intensity in a more intuitive and manageable way. The decibel scale is defined as L = 10 * log10(I/I0), where L is the loudness in decibels, I is the intensity of the sound, and I0 is the reference intensity level. This logarithmic scale compresses the extensive range of sound intensities into a more compact scale, making it easier to analyse and compare different sound levels. It also aligns more closely with human perception of sound, as we perceive sound intensity logarithmically.

In chemistry, the pH of a solution is calculated using logarithms. The pH is defined as pH = -log10([H+]), where [H+] is the concentration of hydrogen ions in the solution. The logarithmic scale is used because [H+] can vary over a wide range, and the logarithm helps to simplify these numbers into a more manageable scale, from 0 to 14. A lower pH (below 7) indicates an acidic solution, while a higher pH (above 7) indicates a basic solution. The logarithmic nature of the pH scale allows scientists to easily compare the relative acidity or basicity of solutions.

The change of base formula is crucial because it allows us to compute logarithms with any base using logarithms of a different, perhaps more convenient, base. This is especially useful when working with bases that are not readily available on standard calculators. For instance, most calculators only have buttons for natural logarithms (base e) and common logarithms (base 10). The change of base formula, logb(a) = logc(a) / logc(b), allows us to calculate logarithms in base b using base c, facilitating calculations and solving equations with various bases, thereby providing flexibility and ease in computations.

Practice Questions

Given the equation 2 * log_2(x) - log_2(8) = 3, solve for x.

To solve the equation 2 * log2(x) - log2(8) = 3, we first simplify the equation using logarithm properties. We know that log2(8) = 3 because 23 = 8. Substituting this into the equation, we get 2 * log2(x) - 3 = 3. Next, we add 3 to both sides of the equation, resulting in 2 * log2(x) = 6. Dividing both sides by 2 gives us log2(x) = 3. Finally, to find the value of x, we rewrite the equation in exponential form: x = 23 = 8. Therefore, the solution to the equation is x = 8.

Solve the equation log_3(2x + 1) = 4 for x.

To find the value of x in the equation log3(2x + 1) = 4, we first rewrite the equation in exponential form to eliminate the logarithm: 2x + 1 = 34. Calculating the exponent, we get 2x + 1 = 81. Next, we subtract 1 from both sides of the equation: 2x = 80. Finally, we divide by 2 to isolate x: x = 40. Therefore, the solution to the equation is x = 40. This method of converting the logarithmic equation into its exponential form is a common technique for solving logarithmic equations and is crucial for understanding the relationship between logarithms and exponents.

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