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CIE IGCSE Maths Study Notes

7.3.1 Vector Magnitude Calculation

Understanding the magnitude of a vector is fundamental in the study of vectors in physics and mathematics. The magnitude of a vector describes its length and is a scalar quantity. In this section, we will explore how to calculate the magnitude of a vector given its components along the x and y axes.

Introduction to Vector Magnitude

Vectors are mathematical entities with both magnitude and direction. The magnitude of a vector (often denoted as |v|) is a measure of its length. For a two-dimensional vector v with components x and y, the magnitude can be calculated using the Pythagorean theorem.

Vector Magnitude

Calculating Magnitude

The magnitude of a vector v = (x,y)(x, y) is given by the formula:

v=x2+y2|v| = \sqrt{x^2 + y^2}

This formula arises from the Pythagorean theorem, applied to a right-angled triangle formed by the components of the vector.

Magnitude of a Vector Formula

Image courtesy of Cue Math

Key Concepts

  • Vector Components: The x and y values that define the direction and magnitude of the vector in two dimensions.
  • Pythagorean Theorem: A fundamental relation in Euclidean geometry among the three sides of a right triangle.
  • Square Root: The function that returns the positive square root of a number.

Example 1: Basic Calculation

Given vector v = (3,4)(3, 4), calculate its magnitude.

v=32+42|v| = \sqrt{3^2 + 4^2}v=9+16|v| = \sqrt{9 + 16}v=25=5|v| = \sqrt{25} = 5

Magnitude = 5 units

Magnitude of Vector (3,4)

Example 2: Negative Components

Given vector v = (6,8)(-6, 8), calculate its magnitude.

v=(6)2+82|v| = \sqrt{(-6)^2 + 8^2}v=36+64|v| = \sqrt{36 + 64}v=100=10|v| = \sqrt{100} = 10

Magnitude = 10 units

Magnitude of Vector (-6,8)

Example 3: Decimal Components

Given vector v = (0.5,2.5)(0.5, -2.5), calculate its magnitude.

v=0.52+(2.5)2|v| = \sqrt{0.5^2 + (-2.5)^2}v=0.25+6.25|v| = \sqrt{0.25 + 6.25}v=6.52.55|v| = \sqrt{6.5} \approx 2.55

Magnitude ≈ 2.55 units

Magnitude of Vector (0.5, -2.5)

Practice Questions

Question 1:

For vector (7,24)(7, -24), calculate its magnitude.

v=72+(24)2|v| = \sqrt{7^2 + (-24)^2}v=49+576|v| = \sqrt{49 + 576}v=625=25|v| = \sqrt{625} = 25

Magnitude = 25 units

Magnitude of Vector (7,-24)

Question 2:

For vector (3.5,2.5)(-3.5, 2.5), calculate its magnitude.

v=(3.5)2+2.52|v| = \sqrt{(-3.5)^2 + 2.5^2}v=12.25+6.25|v| = \sqrt{12.25 + 6.25}v=18.54.3|v| = \sqrt{18.5} \approx 4.3

Magnitude ≈ 4.3 units

Magnitude of Vector (-3.5, 2.5)

Tips for Success

  • Remember to square the components before adding them; this eliminates any negative signs.
  • The magnitude is always a positive value or zero.
  • Practice with vectors in different quadrants to become comfortable with positive and negative components.

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