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CIE IGCSE Maths Study Notes

6.2.1 Trigonometric Ratios

Understanding trigonometric ratios is a fundamental part of trigonometry, a branch of mathematics that deals with the relationships between the sides and angles of triangles. This section focuses on the basic trigonometric ratios: sine (sin), cosine (cos), and tangent (tan), which are essential for solving problems related to right-angled triangles. By mastering these concepts, students can easily calculate unknown sides or angles, paving the way for more complex applications in geometry and beyond.

Trigonometric Ratios

Image courtesy of Passey’s World of Mathematics

Introduction to Trigonometric Ratios

In any right-angled triangle, the three primary trigonometric ratios are defined as follows:

  • Sine (sin) of an angle is the ratio of the length of the opposite side to the length of the hypotenuse.
  • Cosine (cos) of an angle is the ratio of the length of the adjacent side to the length of the hypotenuse.
  • Tangent (tan) of an angle is the ratio of the length of the opposite side to the length of the adjacent side.

Calculating Sides using Trigonometric Ratios

Example 1: Finding an Unknown Side

Problem: In a right-angled triangle, if the angle adjacent to the side you are trying to find is 30°, and the hypotenuse is 10 cm long, calculate the length of the adjacent side.

Solution:

1. Identify the known values: Angle = 30°, Hypotenuse = 10 cm.

2. Choose the appropriate trigonometric ratio: Since we have the hypotenuse and need to find the adjacent side, we use the cosine ratio.

cos(30°)=Adjacent sideHypotenuse\cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

3. Rearrange the formula to solve for the unknown side:

Adjacent side=cos(30°)×Hypotenuse\text{Adjacent side} = \cos(30°) \times \text{Hypotenuse}

4. Calculate:

Adjacent side=cos(30°)×10=8.66cm\text{Adjacent side} = \cos(30°) \times 10 = 8.66 \, \text{cm}

(Note: The cosine of 30° is approximately 0.866)

Example 2: Calculating the Opposite Side

Problem: Find the length of the opposite side in a right-angled triangle if the angle opposite the side is 45° and the hypotenuse is 10 cm.

Solution:

1. Identify the known values: Angle = 45°, Hypotenuse = 10 cm.

2. Select the trigonometric ratio: We use the sine ratio since we have the hypotenuse and need to find the opposite side.

sin(45°)=Opposite sideHypotenuse\sin(45°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

3. Rearrange the formula:

Opposite side=sin(45°)×Hypotenuse\text{Opposite side} = \sin(45°) \times \text{Hypotenuse}

4. Calculate:

Opposite side=sin(45°)×10=7.07cm\text{Opposite side} = \sin(45°) \times 10 = 7.07 \, \text{cm}

(Note: The sine of 45° is approximately 0.707)

Calculating Angles using Trigonometric Ratios

To find an angle in a right-angled triangle when we know the lengths of two sides, we can use the inverse trigonometric functions: arcsin, arccos, and arctan.

Example 3: Finding an Angle

Problem: Calculate the angle opposite the side of length 7 cm in a right-angled triangle with a hypotenuse of 10 cm.

Solution:

1. Identify the known values: Opposite side = 7 cm, Hypotenuse = 10 cm.

2. Choose the trigonometric ratio: The sine ratio is suitable here.

sin(θ)=Opposite sideHypotenuse\sin(\theta) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

3. Insert the known values and solve for the angle:

sin(θ)=710\sin(\theta) = \frac{7}{10}

4. Calculate the angle using the inverse sine function:

θ=sin1(710)=44.42°\theta = \sin^{-1}\left(\frac{7}{10}\right) = 44.42°

Practice Questions

Question 1

A ladder is leaning against a wall, touching the wall at a height of 6 meters. If the angle between the ground and the ladder is 60°, find the length of the ladder.

Solution:

1. Given:

  • Angle θ=60\theta = 60^\circ
  • Height (opposite side) h=6h = 6 meters

2. Formula:

The length of the ladder (hypotenuse, LL) can be found using the sine formula:

sin(θ)=oppositehypotenuse\sin(\theta) = \dfrac{\text{opposite}}{\text{hypotenuse}}

3. Substituting the known values:

sin(60)=6L\sin(60^\circ) = \dfrac{6}{L}

4. Solve for LL, rearrange the formula:

L=6sin(60)L = \dfrac{6}{\sin(60^\circ)}

Using the value sin(60)=32\sin(60^\circ) = \dfrac{\sqrt{3}}{2}:

L=632L = \dfrac{6}{\dfrac{\sqrt{3}}{2}}

L=6×23L = \dfrac{6 \times 2}{\sqrt{3}}

L=123L = \frac{12}{\sqrt{3}}

L=43L = 4\sqrt{3} metres

Thus, the length of the ladder is 434\sqrt{3} metres.

Question 2:

In a right-angled triangle, if one of the angles is 53° and the adjacent side to this angle is 12 cm, calculate the length of the hypotenuse.

Solution:

1. Given:

  • Adjacent side (a)(a) = 12 cm
  • Angle (θ)(\theta) = 53°

2. Relationship:

  • cos(θ)=ah\cos(\theta) = \dfrac{a}{h}, where hh is the hypotenuse.

3. Rearrange for (h):

  • h=acos(θ)h = \dfrac{a}{\cos(\theta)}

4. Substitute values:

  • h=12cos(53)h = \dfrac{12}{\cos(53^\circ)}
  • h19.94cmh \approx 19.94 \text{cm}

Thus, the length of the hypotenuse is approximately 19.94 centimetres.

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