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CIE IGCSE Maths Study Notes

3.7.2 Finding Perpendicular Lines

In coordinate geometry, understanding how to find the gradient and equation of a line perpendicular to a given line is vital. This section focuses on the mathematical techniques for determining these with precision, tailored for CIE IGCSE students.

Perpendicular lines

Image courtesy of Isaac Physics

Understanding Gradients

The gradient of a line indicates its steepness. For a line y=mx+cy = mx + c, mmrepresents the gradient. Two lines are perpendicular if the product of their gradients equals 1-1.

Gradient of Perpendicular Lines

The gradient of a line perpendicular to another is the negative reciprocal of the original line's gradient. If a line has a gradient mm, then the perpendicular line's gradient is 1m-\dfrac{1}{m}.

Calculating the Gradient of a Perpendicular Line

Example 1: Gradient Calculation

Given 2y=3x+12y = 3x + 1, find the gradient of a line perpendicular to it.

  • Original line in slope form: y=32x+12y = \frac{3}{2}x + \frac{1}{2}
  • Original gradient (m)(m) : 32 \frac{3}{2}
  • Perpendicular gradient (mperpendicular)(m_{\text{perpendicular}}): 132=23-\frac{1}{\frac{3}{2}} = -\frac{2}{3}

Finding the Equation of a Line Perpendicular to a Given Line

Given a point and the perpendicular gradient, use the formula yy1=m(xx1)y - y_1 = m(x - x_1) to find the equation.

Example 2: Equation of a Perpendicular Line

Find the equation of a line perpendicular to y=2x+5y = -2x + 5 passing through (3,4)(3, 4).

  • Perpendicular gradient: 12\frac{1}{2}
  • Equation using point (3,4)(3, 4): y4=12(x3)y - 4 = \frac{1}{2}(x - 3)
  • Simplified equation: y=12x+2.5y = \frac{1}{2}x + 2.5

Graphical Representation:

Graph of Perpendicular Lines

Practice Questions

Question 1:

Given the line equation 4xy=84x - y = 8, calculate the gradient of a line perpendicular to it and find its equation if it passes through the point (1,2)(-1, -2).

Solution:

  • Given line's gradient: 44
  • Perpendicular gradient: 14=0.25-\frac{1}{4} = -0.25
  • Equation: y(2)=0.25(x(1))y - (-2) = -0.25(x - (-1))
  • Simplified equation: y=0.25x2.25y = -0.25x - 2.25

Graphical Representation:

Graph of Perpendicular Lines

Question 2:

The line y=45x3y = \frac{4}{5}x - 3 has a perpendicular line passing through the point (2,3)(2, 3). Determine the equation of this perpendicular line.

Solution:

  • Given line's gradient: 45\frac{4}{5}
  • Perpendicular gradient: 54=1.25-\frac{5}{4} = -1.25
  • Equation: y3=1.25(x2)y - 3 = -1.25(x - 2)
  • Simplified equation: y=1.25x+5.5y = -1.25x + 5.5

Graphical Representation:

Graph of Perpendicular Lines

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