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CIE IGCSE Maths Study Notes

3.5.1 Interpreting and Formulating Linear Equations

Understanding the equations of straight-line graphs is foundational in coordinate geometry. This section delves into interpreting and formulating linear equations, emphasizing various forms such as y=mx+cy = mx + c and ax+by=cax + by = c, focusing on identifying the gradient (slope) and y-intercept.

Linear function graph

Image courtesy of HMH

What is a Linear Equation?

A linear equation represents a straight line on a coordinate plane, typically expressed in the form y=mx+cy = mx + c, where:

  • mm is the gradient, determining the steepness and direction of the line.
  • cc is the y-intercept, indicating where the line crosses the y-axis.

Another common form is ax+by=cax + by = c, which can be rearranged into y=mx+cy = mx + c or other required forms.

Interpreting Straight-Line Graphs

To interpret straight-line graphs, one must grasp two main components: the gradient and the y-intercept.

  • Gradient (m): Shows the change in yy for a unit change in xx. Positive gradients indicate an upward slope, negative gradients a downward slope, and a zero gradient indicates a horizontal line.
  • Y-intercept (c): The point where the line intersects the y-axis, determined by the yy value when x=0x = 0.

Formulating Linear Equations

Creating equations of straight lines involves finding the gradient and y-intercept from a graph or set of points.

From a Graph

Directly identify the y-intercept where the line crosses the y-axis. To find the gradient, select two points on the line, applying:

m=y2y1x2x1m = \dfrac{{y_2 - y_1}}{{x_2 - x_1}}Slope

From Points

Given two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), calculate the gradient using the same formula for mm. Once mm is known, use y=mx+cy = mx + c with one point to solve for cc.

Slope illustration

Image courtesy of CueMath

Worked Examples

Example 1: Finding the Equation from a Gradient and a Point

Given a gradient m=3m = -3 and a point (2,3)(-2, 3), find the equation of the line.

Solution:

1. Using the formula y=mx+cy = mx + c, we substitute m=3m = -3 and the point (2,3)(-2, 3) to solve for cc:

3=(3)(2)+c3 = (-3)(-2) + c3=6+c3 = 6 + c36=c3 - 6 = cc=3c = -3

2. Solving for cc, we find c=3c = -3.

Thus, the equation of the line is:

y=3x3y = -3x - 3

Example 2: Determining Gradient and Y-intercept from an Equation

Given the equation 3x4y=123x - 4y = 12, rearrange it to the form y=mx+cy = mx + c to identify the gradient and y-intercept.

Solution:

1. Rearrange the equation:

4y=3x+124y = -3x + 12y=34x+3y = \dfrac{-3}{4}x + 3

2. Gradient (mm): 34-\dfrac{3}{4}

3. Y-intercept (cc): 33

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