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CIE A-Level Maths Study Notes

1.6.2 Recognising Sequences

In the realm of mathematics, particularly within algebra, sequences play a pivotal role. They are essentially ordered lists of numbers that adhere to a specific pattern. This section delves into two primary types of sequences: Arithmetic Progressions (AP) and Geometric Progressions (GP). These sequences are integral for understanding numerical patterns and relationships.

Arithmetic Progressions (AP)

An Arithmetic Progression is a sequence where each term after the first is derived by adding a constant, known as the common difference, to the preceding term.

Definition and Formula

  • General Form: An AP is denoted as a,a+d,a+2d,a+3d,a, a+d, a+2d, a+3d, \ldots, where aa represents the first term and dd is the common difference.
  • Nth Term Formula: The nth term of an AP is given by an=a+(n1)da_n = a + (n - 1)d.
  • Sum Formula: The sum of the first n terms of an AP is calculated as Sn=n2(2a+(n1)d).S_n = \frac{n}{2}(2a + (n - 1)d).

Example 1: Finding the 10th Term of a Sequence

Find the 10th term of the sequence 3,7,11,3, 7, 11, \ldots.

Solution:

1. Identify the First Term and Common Difference

  • First term (a)(a) = 3
  • Common difference (d)(d) = 7 - 3 = 4

2. Apply the Formula for the (n)th Term of an Arithmetic Progression (AP)

  • The nthnth term of an AP is given by: an=a+(n1)d a_n = a + (n - 1)d
  • For the 10th term (a10):a10=3+(101)×4(a{10}): a{10} = 3 + (10 - 1) \times 4
  • Calculate: a10=3+9×4=3+36=39a_{10} = 3 + 9 \times 4 = 3 + 36 = 39

Answer:

The 10th term of the sequence is 39.

Example 2: 20th Term and Sum of the First 20 Terms

Determine the 20th term and the sum of the first 20 terms of the sequence 4,9,14,4, 9, 14, \ldots

Solution:

1. Identify the First Term and Common Difference:

  • First term (a)(a) = 4
  • Common difference (d)(d) = 9 - 4 = 5

2. Find the 20th Term:

  • Apply the nnth term formula: a20=4+(201)×5a_{20} = 4 + (20 - 1) \times 5
  • Calculate: a20=4+19×5=4+95=99a_{20} = 4 + 19 \times 5 = 4 + 95 = 99

3. Calculate the Sum of the First 20 Terms:

  • The sum of the first nn terms of an AP is given by: Sn=n2[2a+(n1)d]S_n = \frac{n}{2} [2a + (n - 1)d]
  • For the first 20 terms (S20):(S_{20}): S20=202[2×4+(201)×5]S_{20} = \frac{20}{2} [2 \times 4 + (20 - 1) \times 5]
  • Calculate: S20=10[8+19×5]=10[8+95]=10×103=1030S_{20} = 10 [8 + 19 \times 5] = 10 [8 + 95] = 10 \times 103 = 1030

Geometric Progressions (GP)

A Geometric Progression is a sequence in which each term after the first is obtained by multiplying the previous term by a fixed, non-zero number called the common ratio.

Definition and Formula

  • General Form: A GP is represented as a,ar,ar2,ar3,a, ar, ar^2, ar^3, \ldots, where aa is the first term and rr is the common ratio.
  • Nth Term Formula: The nth term of a GP is an=arn1a_n = ar^{n-1}.
  • Sum Formula: The sum of the first n terms of a GP is Sn=a1rn1rS_n = a\frac{1 - r^n}{1 - r}, for r1r \neq 1.

Example 1: Sum of the First 5 Terms of a Geometric Sequence

Find the sum of the first 5 terms of the sequence 2,6,18,54,2, 6, 18, 54, \ldots

Solution:

1. Identify the First Term and Common Ratio

  • First term (a)(a) = 2
  • Common ratio (r)(r) = 62=3\frac{6}{2} = 3

2. Apply the Formula for the Sum of the First nn Terms of a Geometric Progression (GP)

  • The sum of the first nn terms of a GP is given by: Sn=a1rn1rS_n = a \frac{1 - r^n}{1 - r}
  • For the first 5 terms (S5)(S_5): S5=213513S_5 = 2 \frac{1 - 3^5}{1 - 3}
  • Calculate: S5=2124313=22422=242S_5 = 2 \frac{1 - 243}{1 - 3} = 2 \frac{-242}{-2} = 242

Answer:

The sum of the first 5 terms of the sequence is 242.

Example 2: 7th Term and Sum of the First 7 Terms of a Geometric Sequence

Determine the 7th term and the sum of the first 7 terms of the sequence (5,10,20,40,5, 10, 20, 40, \ldots

Solution:

1. Identify the First Term and Common Ratio

  • First term (a)(a) = 5
  • Common ratio (r)(r) = 105\frac{10}{5} = 2

2. Find the 7th Term

  • The nnth term of a GP is given by: an=a×rn1a_n = a \times r^{n-1}
  • For the 7th term (a7)(a_7): a7=5×271=5×26a_7 = 5 \times 2^{7-1} = 5 \times 2^6
  • Calculate: a7=5×64=320a_7 = 5 \times 64 = 320

3. Calculate the Sum of the First 7 Terms

  • The sum of the first nn terms of a GP is given by: Sn=a1rn1rS_n = a \frac{1 - r^n}{1 - r}
  • For the first 7 terms (S7)(S_7): S7=512712S_7 = 5 \frac{1 - 2^7}{1 - 2}
  • Calculate: S7=511281=5×127=635S_7 = 5 \frac{1 - 128}{-1} = 5 \times 127 = 635

Answer

The seventh term of the sequence is 320 and the sum of the sequence is 635.

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