TutorChase logo
AQA GCSE Maths (Higher) Study Notes

3.1.1 Understanding Ratios

Ratios are crucial in mathematics for comparing quantities. Simplifying ratios and dividing quantities according to ratios are essential skills for a variety of real-world applications.

Ratio

Simplifying Ratios

Reducing ratios to their simplest form involves finding the greatest common divisor (GCD) of the numbers and dividing them by it.

Simplify the ratio 20:30:40

1. GCD of 20, 30, 40 is 10.

2. Simplified Ratio: 2010:3010:4010=2:3:4\frac{20}{10} : \frac{30}{10} : \frac{40}{10} = 2 : 3 : 4

Simplify the ratio 45:60:90

1. GCD of 45, 60, 90 is 15.

2. Simplified Ratio: 4515:6015:9015=3:4:6\frac{45}{15} : \frac{60}{15} : \frac{90}{15} = 3 : 4 : 6

Dividing Quantities in a Ratio

This involves calculating the value of a single part in the ratio and then distributing the total quantity accordingly.

Divide £120 in the ratio 2:3:4

1. Total Parts: 2+3+4=92 + 3 + 4 = 9

2. Value per Part: £1209=£13.33\frac{£120}{9} = £13.33

3. Distribution:

  • Person 1: 2×£13.33=£26.672 \times £13.33 = £26.67
  • Person 2: 3×£13.33=£40.003 \times £13.33 = £40.00
  • Person 3: 4×£13.33=£53.334 \times £13.33 = £53.33

Divide £180 in the ratio 3:2:5

  1. Total Parts: 3+2+5=103 + 2 + 5 = 10
  2. Value per Part: £18010=£18.00\frac{£180}{10} = £18.00
  3. Distribution:
    • Part 1: 3×£18.00=£54.003 \times £18.00 = £54.00
    • Part 2: 2×£18.00=£36.002 \times £18.00 = £36.00
    • Part 3: 5×£18.00=£90.005 \times £18.00 = £90.00

Worked Problems

Problem 1: Ratio Application in Recipes

Suppose a recipe for a cake requires ingredients in the ratio 2:3:4. If you have 900g of the first ingredient, how much of the other two ingredients do you need?

Solution:

  1. Given Ratio: 2:3:4.
  2. Total parts of the given ingredient: 900 g/2=450 g900 \ g / 2 = 450 \ g per part.
  3. Required quantities:
    • Second ingredient: 3×450 g=1350 g3 \times 450 \ g = 1350 \ g.
    • Third ingredient: 4×450 g=1800 g4 \times 450 \ g = 1800 \ g.

Problem 2: Mixing Paints

To get a particular shade of green, a painter mixes yellow and blue paint in the ratio 3:2. If the painter needs 500ml of green paint, how much of each colour does he use?

Solution:

  1. Total Ratio Parts: 3+2=53 + 2 = 5.
  2. Total Paint: 500 ml
  3. Value per Part: 500ml5=100ml\frac{500ml}{5} = 100ml
  4. Quantities:
    • Yellow paint: 3×100ml=300ml3 \times 100ml = 300ml
    • Blue paint: 2×100ml=200ml2 \times 100ml = 200ml

Hire a tutor

Please fill out the form and we'll find a tutor for you.

1/2
About yourself
Alternatively contact us via
WhatsApp, Phone Call, or Email