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AQA GCSE Maths (Higher) Study Notes

2.1.2 Substitution in Expressions

Substitution in algebraic expressions is a critical skill that enables students to replace variables with given numerical values. This process simplifies expressions or equations, making them easier to evaluate or solve. Mastery of substitution is essential for success in mathematics and its applications.

What is Substitution?

Substitution involves replacing algebraic variables with specific numbers. It's a straightforward yet powerful technique to evaluate expressions and solve equations.

Substitution in Expressions

Image courtesy of All About Circuits

Key Concepts

  • Variables as placeholders: They represent unknown or generalized numbers.
  • Numerical substitution: Inserting numbers for variables to simplify expressions.
  • Order of operations: Adhering to BIDMAS (Brackets, Indices, Division and Multiplication, Addition and Subtraction) when performing substitutions.

Substituting Values into Expressions

To substitute effectively:

1. Identify the variable(s) in the expression.

2. Determine the numerical value for each variable.

3. Substitute and simplify the expression according to the order of operations.

Example 1: Simple Substitution

Given the expression 3x+43x + 4 and x=2x = 2, substitute and simplify:

1. Substitute xx with 22: 3(2)+43(2) + 4

2. Simplify: 6+4=106 + 4 = 10

Final answer: 1010

Example 2: Multiple Variables

For 2x+3y2x + 3y with x=3x = 3 and y=2y = 2:

1. Substitute x=3x = 3 and y=2y = 2: 2(3)+3(2)2(3) + 3(2)

2. Simplify: 6+6=126 + 6 = 12

Final answer: 1212

Substitution in Formulas

Substitution also applies to formulas in various mathematical and real-world contexts.

Example 3: Applying Formulas

To find the area AA of a rectangle where l=5l = 5 cm and w=3w = 3 cm:

1. Formula: A=l×wA = l \times w

2. Substitute l=5l = 5 and w=3w = 3: 5×35 \times 3

3. Simplify: 1515

Final answer: 15 cm 215 \text{ cm }^2

Practical Questions

Question 1

Given 4x74x - 7 and x=3x = 3, find the value.

1. Substitute: 4(3)74(3) - 7

2. Simplify: 127=512 - 7 = 5

Final answer: 55

Question 2

For a square with perimeter P=20P = 20 cm and P=4sP = 4s, find ss.

1. Rearrange: s=P4s = \frac{P}{4}

2. Substitute: s=204s = \frac{20}{4}

3. Simplify: s=5s = 5

Final answer: 55 cm

Question 3

If y=2x+5y = 2x + 5 and x=4x = 4, find yy.

1. Substitute: y=2(4)+5y = 2(4) + 5

2. Simplify: y=8+5=13y = 8 + 5 = 13

Question 4

Calculate the value of 7x24x+37x^2 - 4x + 3 for x=1x = -1.

1. Substitute: 7(1)24(1)+37(-1)^2 - 4(-1) + 3

2. Simplify: 7(1)+4+3=147(1) + 4 + 3 = 14

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