What is the magnitude of vector (11, 60)?

The magnitude of the vector (11, 60) is approximately 61.

To find the magnitude of a vector, you use the Pythagorean theorem. The vector (11, 60) can be thought of as a right-angled triangle where 11 and 60 are the lengths of the two perpendicular sides. The magnitude of the vector is the length of the hypotenuse of this triangle.

The formula to calculate the magnitude of a vector (a, b) is √(a² + b²). In this case, a is 11 and b is 60. So, you need to square both numbers, add them together, and then take the square root of the result.

First, calculate the squares: 11² = 121 and 60² = 3600. Next, add these squares together: 121 + 3600 = 3721. Finally, take the square root of 3721, which is √3721 = 61. Therefore, the magnitude of the vector (11, 60) is 61.

Understanding how to find the magnitude of a vector is important in many areas of mathematics and physics, as it helps you determine the length or size of the vector, which can represent things like force, velocity, or displacement.