What is the hypotenuse of a triangle with sides 11 cm and 60 cm?

The hypotenuse of a right-angled triangle with sides 11 cm and 60 cm is approximately 61 cm.

To find the hypotenuse of a right-angled triangle, we use Pythagoras' Theorem. This theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. Mathematically, this is written as \( c^2 = a^2 + b^2 \), where \( c \) is the hypotenuse, and \( a \) and \( b \) are the other two sides.

In this case, the sides are 11 cm and 60 cm. Plugging these values into the formula, we get:
\[ c^2 = 11^2 + 60^2 \]
\[ c^2 = 121 + 3600 \]
\[ c^2 = 3721 \]

To find \( c \), we take the square root of 3721:
\[ c = \sqrt{3721} \]
\[ c \approx 61 \]

So, the hypotenuse is approximately 61 cm. This method is very useful for solving problems involving right-angled triangles, and it's a fundamental concept in GCSE Maths. Remember, always ensure your triangle is right-angled before applying Pythagoras' Theorem.