How do you simplify (4^3) × (4^(-1))?

To simplify \((4^3) \times (4^{-1})\), you get \(4^{3-1} = 4^2\).

When simplifying expressions involving exponents, one useful rule is the product of powers rule. This rule states that when you multiply two powers with the same base, you can add the exponents. In this case, the base is 4. So, you have \(4^3\) and \(4^{-1}\).

According to the product of powers rule, you add the exponents together: \(3 + (-1)\). This simplifies to \(3 - 1\), which equals 2. Therefore, \((4^3) \times (4^{-1})\) simplifies to \(4^2\).

To break it down further, \(4^3\) means \(4 \times 4 \times 4\), which equals 64. On the other hand, \(4^{-1}\) means \(\frac{1}{4}\). When you multiply 64 by \(\frac{1}{4}\), you get 16, which is the same as \(4^2\). So, the simplified form of \((4^3) \times (4^{-1})\) is indeed \(4^2\).