What's the integral of x^4*ln(x)?

The integral of x^4*ln(x) is (1/5)x^5*ln(x) - (1/25)x^5 + C.

To solve this integral, we will use integration by parts. Let u = ln(x) and dv = x^4 dx. Then du = 1/x dx and v = (1/5)x^5. Using the formula for integration by parts, we have:

∫x^4 ln(x) dx = uv - ∫v du
= (1/5)x^5 ln(x) - ∫(1/5)x^4 dx
= (1/5)x^5 ln(x) - (1/25)x^5 + C

Therefore, the integral of x^4 ln(x) is (1/5)x^5 ln(x) - (1/25)x^5 + C.