Solve the equation 2^x = 8.

The solution to 2^x = 8 is x = 3.

To solve this equation, we need to use logarithms. Specifically, we need to take the logarithm of both sides of the equation with base 2, since 2 is the base of the exponent in the left-hand side of the equation. This gives us:

log2(2^x) = log2(8)

Using the property of logarithms that states loga(b^c) = c*loga(b), we can simplify the left-hand side of the equation:

x*log2(2) = log2(8)

Since log2(2) = 1, we can simplify further:

x = log2(8)

Now we just need to evaluate log2(8). This means finding the exponent to which we need to raise 2 to get 8. In other words, we need to solve the equation 2^y = 8. We can see that y = 3 satisfies this equation, since 2^3 = 8. Therefore:

x = log2(8) = 3

So the solution to 2^x = 8 is x = 3.