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The roots of x^2 - 4x + 4 = 0 are both x = 2.
To find the roots of a quadratic equation in the form ax^2 + bx + c = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = -4, and c = 4. Substituting these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2 - 4(1)(4))) / 2(1)
x = (4 ± √(16 - 16)) / 2
x = (4 ± 0) / 2
Simplifying, we get:
x = 2
Therefore, the roots of x^2 - 4x + 4 = 0 are both x = 2. We can also check this by factoring the quadratic equation:
x^2 - 4x + 4 = (x - 2)(x - 2)
Since the two factors are the same, the only solution is x = 2.
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