Evaluate the integral of ln(x) dx.

The integral of ln(x) dx is xln(x) - x + C, where C is the constant of integration.

To evaluate the integral of ln(x) dx, we use integration by parts. Let u = ln(x) and dv = dx. Then du/dx = 1/x and v = x. Using the formula for integration by parts, we have:

∫ln(x) dx = xln(x) - ∫(1/x)(x) dx
= xln(x) - ∫dx
= xln(x) - x + C

Therefore, the integral of ln(x) dx is xln(x) - x + C, where C is the constant of integration. This result can be verified by differentiating xln(x) - x + C with respect to x, which gives ln(x) as the derivative.