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The derivative of y = csc(5x) is -5csc(5x)cot(5x).
To differentiate y = csc(5x), we can use the chain rule and the derivative of csc(x) which is -csc(x)cot(x). Let u = 5x, then y = csc(u). Using the chain rule, we have:
dy/dx = dy/du * du/dx
dy/du = -csc(u)cot(u) (derivative of csc(u))
du/dx = 5 (derivative of 5x)
Substituting these values, we get:
dy/dx = -csc(5x)cot(5x) * 5
dy/dx = -5csc(5x)cot(5x)
Therefore, the derivative of y = csc(5x) is -5csc(5x)cot(5x).
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