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The derivative of tan(x) is sec^2(x).
To find the derivative of tan(x), we can use the quotient rule. Recall that tan(x) = sin(x)/cos(x). Therefore, we have:
tan'(x) = [cos(x)(sin'(x)) - sin(x)(cos'(x))] / cos^2(x)
Using the derivatives of sin(x) and cos(x), we get:
tan'(x) = [cos(x)cos(x) - sin(x)(-sin(x))] / cos^2(x)
tan'(x) = [cos^2(x) + sin^2(x)] / cos^2(x)
Using the identity cos^2(x) + sin^2(x) = 1, we get:
tan'(x) = 1 / cos^2(x)
Recall that sec(x) = 1 / cos(x). Therefore, we have:
tan'(x) = sec^2(x)
This is the final answer. We have shown that the derivative of tan(x) is sec^2(x).
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