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The derivative of cot(x) is -csc^2(x).
To find the derivative of cot(x), we can use the quotient rule. Recall that cot(x) = cos(x)/sin(x). Therefore,
cot'(x) = [cos'(x)sin(x) - cos(x)sin'(x)]/sin^2(x)
Using the derivatives of sin(x) and cos(x), we get
cot'(x) = [-sin(x)sin(x) - cos(x)cos(x)]/sin^2(x)
Simplifying the numerator, we get
cot'(x) = -[sin^2(x) + cos^2(x)]/sin^2(x)
Recall that sin^2(x) + cos^2(x) = 1, so
cot'(x) = -1/sin^2(x)
Using the identity csc^2(x) = 1/sin^2(x), we can rewrite this as
cot'(x) = -csc^2(x)
Therefore, the derivative of cot(x) is -csc^2(x).
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